12d^2-13d-14=0

Solution for 12d^2-13d-14=0 equation:

12d^2-13d-14=0

a = 12; b = -13; c = -14;
Δ = b2-4ac
Δ = -132-4·12·(-14)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-29}{2*12}=\frac{-16}{24}
=-2/3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+29}{2*12}=\frac{42}{24}
=1+3/4
$